Quick description
This page lists various constructions of new examples of groups and subgroups from known examples, and gives some brief notes of what each construction is good for.
General discussion
This is a list of various standard constructions of groups and subgroups.

Direct products

Semidirect products

Extensions

Central extensions


Fibre products

Wreath products

Amalgamated free products

Free products


HNN extensions

Graphs of groups
Semidirect products
The group law on the direct product is determined by the requirement that for every and . That is, acts on by conjugation, and the action is trivial. The semidirect product construction derives from the observation that any action of on could be used to construct a new group in the same way. Let be a rightaction of on , so for any we have an automorphism of that acts on the right, sending an element to . The semidirect product is in bijection with the set of pairs where and , and the group law is determined by the requirement that .
Often the action is suppressed. By construction, the subgroup of is normal, and the quotient is isomorphic to . So is an extension of by . In fact, any split extension of by is a semidirect product.
Extensions
A group is an extension of a group by a group if there is a short exact sequence
(In other words, the is the quotient of by .) The following example takes advantage of two features of extensions.

The subgroup is to as the trivial subgroup is to .

Often can be chosen to have better properties than . In particular, any presentation for corresponds to an extension where is free.
Example 1
It is a famous and nontrivial fact that there exists a finite group presentation
in which the word problem is unsolvable. That is, there is no algorithm that will tell you whether or not a given word in the generators represents the identity in . (We will not use the fact that is finite in this example. But it will be important in Example 2 below.)
We will use group extensions to produce a different pathology in a much better behaved group—a free group.
Let be the free group on . The relations can be thought of as elements of . By the universal property of free groups, the obvious map extends to a surjection . The kernel of this surjection is precisely , the normal subgroup of generated by the relations. That is, we have a short exact sequence
The fact that the word problem is unsolvable in can now be restated precisely as the assertion that there are normal subgroups of with unsolvable membership problem.
So we see that the existence of the highly pathological group corresponds to a different sort of pathological behaviour in the wellbehaved group
Fibred products
The fibred product construction in the category of groups is the same as in the category of sets. If and are surjections then the fibred product of and is the subgroup of defined as the preimage of the diagonal subgroup of under the map . That is,
Fibred products can be used to improve the finiteness properties of subgroups. Example 1 showed how to construct a nontrivial subgroup of a free group with unsolvable membership problem. Although was finitely generated as a normal subgroup of , it is a consequence of Greenberg's Theorem (Greenberg's Theorem states that every finitely generated normal subgroup of a finitely generated free group is of finite index) that is not finitely generated as a group. In fact, every finitely generated subgroup of a free group has solvable membership problem.
In the following example, we will use a fibred product to construct a finitely generated subgroup of a direct product of two free groups that has unsolvable membership problem.
Example 2
Let be a finitely presented group with unsolvable word problem as in Example 1 and let be the quotient map derived from the presentation. Let be the fibre product of two copies of , a subgroup of . Then
where is the diagonal subgroup of . The membership problem for in is unsolvable, (indeed, is an element of if and only if is trivial in ) and this translates precisely to the statement that the membership problem for in is unsolvable. But the finite set
generates .
We have proved the following.
Wreath products
A wreath product is a special case of a semidirect product. We will first restrict our attention to the wreath product of two finite groups and . The set of set maps
is a group (multiplication comes from multiplication in ) and is naturally equipped with a rightaction of , namely the action by left translation. (It is easy to get confused by the fact that left translation is a right action!) We can think of as the direct sum of copies of , indexed by the elements of , and acts by permuting the factors. This is precisely the data needed for a semidirect product construction.
The wreath product of by is defined to be
where acts on by left translation.
When or may be infinite, we define to be precisely those set maps that equal the identity on all but finitely many elements of . This has the effect that is isomorphic to the direct sum, rather than the direct product, of copies of . Our first example of a wreath product shows how to construct a 2generator group with an abelian subgroup of infinite rank.
Example 3
The group is the direct sum of countably many copies of , and so can be thought of as the group of biinfinite sequences of integers that are equal to zero in all but finitely many coordinates. It admits an action of , where the integer acts by moving the th coordinate to the th coordinate. The orbit of the sequence that is in every nonzero coordinate and in the th coordinate generates . (Here the fact that is the direct sum, rather than the direct product, is important.) The resulting semidirect product is precisely the wreath product . It contains the infiniterank abelian group as a subgroup, and is generated by just two elements.
More generally, given any transitive action of on a set , one can define the wreath product to be the semidirect product of and , where as before acts on by lefttranslation.
Amalgamated free products
Amalgamated free products are pushouts in the category of groups. If and are both injective then the pushout of the corresponding diagram is by definition the amalgamated free product . This is the freest possible group that contains and as subgroups in which the two copies of are identified.
The Seifert–van Kampen Theorem asserts that if a pathconnected topological space can be decomposed as the union of two closed, pathconnected subsets whose intersection is also pathconnected then the fundamental group of is a pushout. Therefore, amalgamated free products arise very naturally in topology.
Example 4
Suppose is a compact orientable surface and is a simple closed curve that is not homotopic to a point. Suppose further that is separating—that is, has two pathcomponents; we shall denote their closures by and . Because is not homotopic to a point, the natural inclusions are injective at the level of for . (This follows from the classification of surfaces.) Therefore
by the Seifert–van Kampen Theorem.
HNN extensions
Example 4 explains what happen at the level of when you cut a surface along a separating curve. But the separating hypothesis is rather unnatural—it makes just as much sense to cut along a nonseparating curve . What happens in this case? The answer is that decomposes as an HNN extension.
Suppose are both injective homomorphisms. If has presentation then the Higman–Neumann–Neumann (HNN) extension is
Example 5
Suppose is a compact orientable surface and is a simple closed curve that is not homotopic to a point. Suppose further that is nonseparating, so has one pathcomponent , and twosided (that is, is not the core of a Möbius band). Then
by the Seifert–van Kampen Theorem.
There are two things to notice about this definition. The first is that, a priori, it seems to depend on the chosen presentation for —however, one can show that the definition is in fact independent of this choice. More importantly, is rather poor notation as it does not specify the maps and . Often, as in Example 5, the two maps are implicit. One way of getting round this ambiguity is to set and write instead of .
Comments
Tensor products are not
Sat, 25/04/2009  05:55 — emertonTensor products are not really defined for groups, but rather for modules
over rings. Abelian groups are modules, and so tensor products are defined for abelian groups, but this is a construction of a very different flavour
to all the other constructions listed on this page.
Perhaps it would be better to have a comment somewhere on the page to this effect
(i.e. that one can define the tensor product of two abelian groups), and then just
link to the How to use tensor products page for more details.
If there are no objections, I will do this some time soon.
I agree
Sat, 25/04/2009  09:28 — JoseBroxYes, I was thinking about the tensor product for abelian groups as a special case of a product construction (in Ring theory it is quite usual to think of everything as modules). Feel free to change it as you say, I added it just as a suggestion (I put it on the list because there really isn't any more on the stub at the moment!)
There could be a link
Mon, 11/05/2009  05:11 — emertonThere could be a link somewhere among the later examples to Use topology to study your group, although I haven't thought very carefully about where it would sit best.