### Quick description

In some situations the existence of a limit can be derived by using inferior or superior limit and suitably dividing a domain to use self-similarity.

### Prerequisites

Basic real analysis.

### Example 1: Maximal density of a packing

Fix a compact domain in Euclidean space (for example, a ball). A packing is then a union of domains congruents to , with disjoint interiors. The density of a packing is defined as

where is the volume and is the square , when the limit exists.

The present trick shows that if is a packing contained in of maximal volume, then exists.

First, since , the superior limit exists. We want to prove that the inferior limit equals the superior one. Given any , there is an such that . Now for any integer the square can be divided into translates of . Each of these contains a packing of density greater than , so that for all . This rewrites as . By maximality, is non-decreasing in ; for all one can introduce and gets . It follows that

so that as soon as is large enough, . As a consequence, and we are done.

### Example 2: Weyl's inequality and polynomial equidistribution

This example is taken from a mathoverflow question and answer.

Let be a polynomial with real coefficients, and irrational. Let

Weyl's Equidistribution theorem for polynomials is equivalent to the claim that as . Though it is not the most easy way to prove this, let us deduce this theorem from the following Weyl's inequality.

Let be a rational number in lowest terms with . Weyl's Inequality is the bound:

If and are both large enough, and of the same order of magnitude, then the right-hand side gets small. The point is that the conditions on prevent one to apply this to arbitrary . However, Dirichlet's theorem tells us that arbitrary high satisfy the needed condition, so that Weyl's inequality implies .

Now the trick comes into play: the right-hand side in Weyl's inequality does not depend on , but only on . It therefore gives a uniform bound simultaneously for the sum and the sums computing using instead of .

For all \varepsilonN_0tS_{N_0}^t<\varepsilon N_0KNK=\lfloor N/N_0 \rfloorS_N\limsup S_N/N=0$.

14 weeks 3 daysago1 year 37 weeksago2 years 9 weeksago2 years 26 weeksago2 years 26 weeksago